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In the triangle below, ∠Q is a right angle. Which ratio would be equivalent to the ratio of sin∠R?

a) cos∠Q
b) cos∠S
c) sin∠Q
d) sin∠S

In the triangle below, ∠Q is a right angle. Which ratio would be equivalent to the-example-1

2 Answers

7 votes

cos<Q

Lets do


\\ \sf\longmapsto sin<R=(P)/(H)


\\ \sf\longmapsto sin<R=(SQ)/(SR)

Now


\\ \sf\longmapsto cos<Q=(B)/(H)


\\ \sf\longmapsto cos<Q=(SQ)/(SR)

User Jhocking
by
8.0k points
7 votes

Answer:

  • b) cos∠S

Explanation:

sin ∠R = SQ/SR

This is same as:

  • cos S

Correct option is b)

User Krzysztof Szynter
by
9.1k points

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