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A line has a slope of m = 12, and the point (-2, 8) lies on the line. What is the slope-intercept form of this linear equation?

User Goppinath
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Final answer:

The slope-intercept form of the linear equation is y = 12x + 32.

Step-by-step explanation:

The slope-intercept form of a linear equation is given by y = mx + b, where m is the slope and b is the y-intercept.

In this case, the slope (m) is given as 12.

We are also given a point (-2, 8) that lies on the line.

Using the point-slope form of a linear equation, we can substitute the values of the slope (m), x-coordinate (-2), and y-coordinate (8) into the equation:

y - y1 = m(x - x1)

8 - 8 = 12(-2 - x)

0 = 12(-2 - x)

0 = -24 - 12x

12x = -24

x = -2

Substituting the value of x into the equation, we can solve for y:

y = mx + b

y = 12(-2) + b

y = -24 + b

Since the point (-2, 8) lies on the line, we can substitute the values of x and y into the equation to solve for b:

8 = -24 + b

b = 32

Therefore, the slope-intercept form of the linear equation is y = 12x + 32.

User Kaseem
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