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Suppose an airplane traveling in a circle at 138 m/s can turn in a circle with as much as 69.6 m/s² of centripetal acceleration. How big will the radius of this circle be?

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Final answer:

The radius of the circle where an airplane can turn with a centripetal acceleration of 69.6 m/s² and at a speed of 138 m/s is approximately 276 meters.

Step-by-step explanation:

To find the radius of the circle in which an airplane traveling at 138 m/s can turn with a centripetal acceleration of 69.6 m/s², we use the formula for centripetal acceleration, which is a = v²/r, where a is the acceleration, v is the velocity, and r is the radius of the circle.

By rearranging the formula to solve for the radius, we get r = v²/a. Plugging in the given values, the radius r is equal to (138 m/s)² / 69.6 m/s², which equals 138² / 69.6. This results in a radius of approximately 276 m.

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