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A 43.0N falling object encounters 7.5N of air resistance. The magnitude of the net force on the object is:

a) 43.0N
b) 7.5N
c) 35.5N
d) 50.5N

1 Answer

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Final answer:

The magnitude of the net force on a 43.0N falling object encountering 7.5N of air resistance is 35.5N, calculated by subtracting the air resistance from the object's weight.

Step-by-step explanation:

The magnitude of the net force on the object can be found by subtracting the force of air resistance from the weight of the object, which is the force due to gravity. The weight of the object is given as 43.0 N and the air resistance is 7.5 N. Therefore, the net force (Fnet) is calculated as follows:

Fnet = weight - air resistance
Fnet = 43.0 N - 7.5 N
Fnet = 35.5 N

So, the magnitude of the net force on the object is 35.5 N, which corresponds to option (c).

User Paolo Rossi
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