Question

Using the quadratic formula to solve 4x - 3x + 9 = 2x + 1, what are the values of x?

a) x = 8
b) x = 5 + 15√3i
c) x = 8, 5 - 15√3i
d) x = 1 + 15√3i, 8

Answer 1

To solve the equation 4x - 3x + 9 = 2x + 1 using the quadratic formula, rearrange the equation into the form ax^2 + bx + c = 0. Then, substitute the values into the quadratic formula and simplify to find the values of x.

Step-by-step explanation:

To solve the equation 4x - 3x + 9 = 2x + 1 using the quadratic formula, we need to rearrange the equation so that it is in the form ax^2 + bx + c = 0.

After rearranging the equation, we get x^2 - 6x + 8 = 0. We can now use the quadratic formula, x = (-b ± √(b^2 - 4ac)) / (2a), where a = 1, b = -6, and c = 8.

Substituting the values, we get x = (6 ± √((-6)^2 - 4(1)(8))) / (2(1)). Simplifying the equation gives us x = (6 ± √(36 - 32)) / 2, which is x = (6 ± √4) / 2.

So, the values of x are x = 8 and x = 5 - 15√3i.