Question

According to the following reaction, how many moles of aluminum oxide will be formed upon the complete reaction of 0.175 moles of iron(III) oxide with excess aluminum?

4Al+3O2→2Al2O3
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Answer 1

0.117 moles of aluminum oxide (Al2O3) will be formed upon the complete reaction of 0.175 moles of iron(III) oxide with excess aluminum based on the stoichiometry of the given reaction.

Step-by-step explanation:

To determine how many moles of aluminum oxide (Al2O3) will be formed from the complete reaction of 0.175 moles of iron(III) oxide with excess aluminum, we use stoichiometry. The balanced chemical equation for the reaction is:

4 Al + 3 Fe2O3 → 6 Fe + 2 Al2O3

From the stoichiometry of the equation, 3 moles of Fe2O3 yield 2 moles of Al2O3. To find the moles of Al2O3 produced from 0.175 moles of Fe2O3, set up a proportion:

(3 moles of Fe2O3 / 2 moles of Al2O3) = (0.175 moles of Fe2O3 / x moles of Al2O3)

Solving for x yields:

x = (0.175 moles of Fe2O3 * 2 moles of Al2O3) / 3 moles of Fe2O3

x ≈ 0.117 moles of Al2O3

Therefore, 0.117 moles of Al2O3 will be produced upon the complete reaction of 0.175 moles of iron(III) oxide with excess aluminum.