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What is the empirical formula for the following compounds?

Vanillin (Vanilla Extract): C9H9O3
Cinnamaldehyde (Cinnamon): C9H8O
Glucose (Sugar): C6H12O6
Eugenol (Cloves): C10H12O2

1 Answer

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Final answer:

The empirical formulas for the compounds mentioned are: Vanillin (Vanilla Extract): C3H3O, Cinnamaldehyde (Cinnamon): C9H8O, Glucose (Sugar): CH2O, Eugenol (Cloves): C5H6O

Step-by-step explanation:

The empirical formula for a compound is the lowest whole-number ratio of the elements in that compound. For example, the molecular formula for glucose is C6H12O6, but the simplest whole-number ratio of the elements in glucose is CH2O.

Similarly, the empirical formulas for the compounds mentioned are:

Vanillin (Vanilla Extract): C3H3O

Cinnamaldehyde (Cinnamon): C9H8O

Glucose (Sugar): CH2O

Eugenol (Cloves): C5H6O

Empirical formulas for the compounds are Vanillin C9H8O3, Cinnamaldehyde C9H8O, Glucose CH2O, and Eugenol C10H12O2; the empirical formulas are either the same as the molecular formulas or the simplest whole-number ratio.

The empirical formula is the simplest whole-number ratio of elements in a compound. Determining the empirical formula for the compounds provided involves reducing the molecular formula to the smallest whole numbers. Here are the empirical formulas for the given compounds:

Vanillin (Vanilla Extract) C9H8O3: The empirical formula is C9H8O3 since the numbers cannot be simplified further.

Cinnamaldehyde (Cinnamon) C9H8O: The empirical formula is C9H8O as it is already in the simplest ratio.

Glucose (Sugar) C6H12O6: The empirical formula is CH2O, by dividing each element’s count by 6.

Eugenol (Cloves) C10H12O2: The empirical formula is C10H12O2, unaffected and simple as given.

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