Question

A mass of 5000 kg is experiencing a 3000 N centripetal force to hold it in a circular path. If the mass has a speed of 6 m/s, what is the radius of the circular path?

Answer 1

The radius of the circular path for a 5000 kg mass experiencing a 3000 N centripetal force and moving with a speed of 6 m/s is 60 meters.

Step-by-step explanation:

To find the radius of the circular path for a mass experiencing a centripetal force, we can use the centripetal force formula: F = m*v^2/r, where F is the centripetal force, m is the mass, v is the velocity, and r is the radius of the circular path. In this instance, a mass of 5000 kg experiencing a 3000 N centripetal force and moving at a speed of 6 m/s will have its radius calculated as follows:

1. Rearrange the formula to solve for r: r = m*v^2/F.
2. Substitute the given values: r = (5000 kg * (6 m/s)^2) / 3000 N.
3. Calculate the radius: r = (5000 kg * 36 m^2/s^2) / 3000 N = 60 m.

Therefore, the radius of the circular path is 60 meters.