Question

Mark is at his house located at (3, 4) on a coordinate plane and walks to the school located at (1, 0). The school is located exactly halfway between Mark's house and Martin's house. To the nearest tenth, what is the distance between Mark's house and Martin's house?

Answer 1

To find the distance between Mark's house and Martin's house, we can use the distance formula which is the square root of the difference between the x-coordinates squared plus the difference between the y-coordinates squared. Plugging in the coordinates, we get a distance of approximately 4.5 units.

Step-by-step explanation:

To find the distance between Mark's house and Martin's house, we can use the distance formula:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

In this case, Mark's house is located at (3, 4) and the school is located at (1, 0). Plugging the coordinates into the formula, we get:

d = sqrt((1 - 3)^2 + (0 - 4)^2)

d = sqrt((-2)^2 + (-4)^2)

d = sqrt(4 + 16)

d = sqrt(20)

d ≈ 4.5

The distance between Mark's house and Martin's house is approximately 4.5 units.