Final answer:
The mass of a sample of sodium containing 3910 atoms is approximately 1.493 × 10^-19 grams.option D) -1.49×10^-19 amu
Step-by-step explanation:
The question asks about the mass of a sample of sodium that contains a specific number of atoms. To find the mass of 3910 sodium atoms, we need to know the atomic mass of sodium and use Avogadro's number for calculations.
The atomic mass of sodium (Na) is approximately 22.9898 atomic mass units (amu). One atomic mass unit has a mass of 1.6605 × 10^-24 grams. To find the mass of one Na atom in grams, we multiply its atomic mass by the mass of one amu:
22.9898 amu × 1.6605 × 10^-24 g/amu = 3.819 × 10^-23 g/atom
To find the mass of 3910 Na atoms, we then multiply the mass of one Na atom by the number of atoms:
3.819 × 10^-23 g/atom × 3910 atoms = 1.493 × 10^-19 grams. This result is the mass of the sodium sample.