Question

Alan has a spinner with 5 areas of equal size. He labeled each area with a different number for a probability experiment. If the probability of the spinner stopping on a multiple of 10 is 3/5, how could Alan have labeled the areas of the spinner?

A) 10, 20, 30, 40, 50
B) 1, 2, 3, 4, 5
C) 5, 10, 15, 20, 25
D) 7, 14, 21, 28, 35

Answer 1

The question incorrectly assumes one of the provided options meets the criteria of a 3/5 probability for landing on a multiple of 10 with a five-area spinner. None of the options match this probability exactly, but Option C is the closest with a 2/5 chance.

Step-by-step explanation:

The student asked how Alan could have labeled the areas of the spinner if the probability of the spinner stopping on a multiple of 10 is 3/5. Since there are 5 areas of equal size on the spinner, each area has a probability of 1/5 of being landed on. Therefore, to have a probability of 3/5 of landing on a multiple of 10, Alan must label three out of the five areas with multiples of 10.

Looking at the given options, we can determine the correct label:

None of the given options exactly matches the required probability of 3/5. However, since the question may be seeking an approximation, Option C is the closest fit, because it has the highest probability (2/5) of landing on a multiple of 10 among the provided options.