Question

What is the proper dissociation equation for the compound Cerium (III) Sulfate?

A. CeSO3 → Ce^3+ + SO4^2-.
B. Ce2(SO4)3 → 2Ce^3+ + 3SO4^2-.
C. Ce(SO4)3 → Ce^3+ + 3SO4^2-.
D. Ce2(SO4)3 → Ce^6+ + 3SO2.

Answer 1

The proper dissociation equation for Cerium (III) Sulfate is Ce2(SO4)3 → 2Ce^3+ + 3SO4^2-, which is option B. It indicates the dissociation of one formula unit of cerium (III) sulfate into two cerium cations and three sulfate anions.

Step-by-step explanation:

The correct dissociation equation for Cerium (III) Sulfate is represented in option B, which is:

Ce2(SO4)3 → 2Ce^3+ + 3SO4^2-.

This equation shows that one formula unit of cerium (III) sulfate dissociates into two cerium cations, each with a charge of +3, and three sulfate anions, each with a charge of -2. Cerium (III) indicates that the cerium has a charge of +3, and since the sulfate ion has a charge of -2, the formula indicates that two cerium ions will balance with three sulfate ions, resulting in the correct formula of Ce2(SO4)3. The stoichiometry of the compound dictates that we write the correct equation considering the charges and the number of ions involved.