Question

If the reaction of 5.87 moles of potassium with excess hydrobromic acid produced an 84.89% yield of hydrogen gas, what was the actual yield of hydrogen gas?

A. 4.98 mol H2
B. 3.47 mol H2
C. 2.94 mol H2
D. 249 mol H2

Answer 1

The actual yield of hydrogen gas is 4.98 mol H2. the actual yield of hydrogen gas, we need to calculate the amount of hydrogen gas produced from the given moles of potassium. Since the reaction has a yield of 84.89%, we can multiply the moles of potassium.

Step-by-step explanation:

To find the actual yield of hydrogen gas, we need to calculate the amount of hydrogen gas produced from the given moles of potassium. Since the reaction has a yield of 84.89%, we can multiply the moles of potassium by this percentage to find the actual yield of hydrogen gas.

Given:

• 5.87 moles of potassium
• 84.89% yield

Actual yield = 5.87 mol K * 84.89% = 4.98 mol H2

the actual yield of hydrogen gas is 4.98 mol H2.

The actual yield of hydrogen gas is 4.98 mol H2. the actual yield of hydrogen gas, we need to calculate the amount of hydrogen gas produced from the given moles of potassium. Since the reaction has a yield of 84.89%, we can multiply the moles of potassium.