Question

In the first 10.0 s s of the reaction, 1.9×10² mol of o₂ is produced in a reaction vessel with a volume of 0.360L . what is the average rate of the reaction over this time interval?

Answer 1

The average rate of the reaction over the 10-second interval is 19 mol/L/s, calculated by dividing the change in concentration of O2, which is 190 mol/L, by the change in time, which is 10.0 seconds.

Step-by-step explanation:

To calculate the average rate of the reaction over the specified time interval, we use the change in concentration of O2 over the change in time. The average rate can be expressed as mol/L/s (M/s).

The change in concentration of O2 (Δ[O2]) is given as 1.9×102 mol in a reaction vessel with a volume of 0.360 L. Therefore, Δ[O2] = 190 mol/L because 1.9×102 mol/0.360 L = 190 mol/L. The time interval (Δt) is 10.0 s.

To find the average rate, we divide the change in concentration by the change in time: Average rate = Δ[O2]/Δt = 190 mol/L / 10.0 s = 19 mol/L/s.

Thus, the average rate of reaction over this 10-second interval is 19 mol/L/s.