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What are the coordinates of A'B'C' if you translate triangle ABC along the vector (5,-2) ?

A) A'(4,4), B'(-3,-1), C'(-7, -3)
B) A'(1,0), B'(5,-5), C(3,-7)
C) A'(-9,4), B'(-5, -1), C'(-7, 7)
D) A'(1,0), B'(0, 2), C(2,0)

User Jeyraof
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1 Answer

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Final answer:

To find the coordinates of A'B'C' after a translation by vector (5,-2), add 5 to the x-coordinates and subtract 2 from the y-coordinates of vertices A, B, and C of the original triangle. Since the given options do not include the original coordinates of triangle ABC, it's impossible to determine which option is correct.

Step-by-step explanation:

The coordinates of A'B'C' after translating triangle ABC along the vector (5,-2) are found by adding the components of the translation vector to the coordinates of each vertex of the original triangle. To perform the translation, we add 5 to the x-coordinate, and subtract 2 from the y-coordinate for each vertex of triangle ABC. Let's assume the coordinates of triangle ABC are A(x1, y1), B(x2, y2), and C(x3, y3). After applying the translation:

  • The coordinates of A' will be (x1 + 5, y1 - 2).
  • The coordinates of B' will be (x2 + 5, y2 - 2).
  • The coordinates of C' will be (x3 + 5, y3 - 2).

Without the original coordinates of A, B, and C, we cannot provide a definitive answer from the choices given.

User Andrey Yaskulsky
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