19.3k views
2 votes
The system below has the solution of (1,3) where A, B, C, D, E, and F are all nonzero real numbers.

Ax+By=C,Dx+Ey=F
Which of the following systems would not have (1,3) as the solution?

A. Ax+By=C and (2A-D)x+(2B+E)y=C-2F
B. Ax+By=C and 7Dx+7Ey=7F
C. Ax+By=C and (A+D)x+(B+E)y=C+F
D. (A/2+D)x+(B/2+E)y=(C/2+F).

1 Answer

5 votes

Final answer:

To identify which system of equations would not have the solution (1,3), we substitute these values into the modified equations. We conclude that option D requires a closer look as it combines modified versions of both original equations, potentially altering the solution.

Step-by-step explanation:

We are given a system of linear equations with a known solution (1,3) and variables A, B, C, D, E, and F. To determine which system would not have (1,3) as the solution, we can substitute the values x = 1 and y = 3 into each system and see if both equations in the system are satisfied.

Analysis of Options

Option D is potentially concerning because it modifies both equations before combining them, which could change the validity of the solution (1,3). We should check this option more closely.

User Thdox
by
7.8k points