Question

A new conveyor system at the local packaging plant will utilize a motor-powered mechanical arm to exert an average force of 890 N to push large crates a distance of 12 meters in 22 seconds. Determine:

a. The work to be performed by the motor.
b. The power output required of the motor.

Answer 1

The work performed by the motor is 10,680 joules, and the power output required of the motor is 485.45 watts.

Step-by-step explanation:

The subject of this question is Physics, and it concerns the topics of work and power. To determine the work performed by the motor, we apply the formula W = F × d, where W is the work, F is the force, and d is the distance. In this case, the motor exerts an average force of 890 N to push the crates a distance of 12 meters. Thus, the work done is W = 890 N × 12 m = 10,680 joules (J).

To calculate the power output required of the motor, we use the formula P = W/t, where P is the power, W is the work done, and t is the time taken. The work performed by the motor is 10,680 J and the time is 22 seconds. So, the power needed is P = 10,680 J / 22 s = 485.45 watts (W).