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67 g of sodium acetate is how many molecules?

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Final answer:

To determine the number of molecules in 67 g of sodium acetate, calculate the number of moles using the molar mass (82.03 g/mol for sodium acetate) and then multiply by Avogadro's number (6.02 x 10^23) to get the number of molecules.

Step-by-step explanation:

To find out how many molecules 67 g of sodium acetate corresponds to, we first need to know the molar mass of sodium acetate (CH₃CO₂Na). While the molar mass of acetic acid (C₂H₄O₂) is given as 60.05 g/mol, sodium acetate has a slightly different molar mass due to the sodium atom. The actual molar mass of sodium acetate is 82.03 g/mol (combining the molar masses of C, H, O, and Na).

Step 1: Calculate the number of moles of sodium acetate:
Number of moles = mass / molar mass
Number of moles = 67 g / 82.03 g/mol

Step 2: Use Avogadro's number to find the number of molecules:
Number of molecules = Number of moles × Avogadro's number
Avogadro's number (Nₙ) = 6.02 × 10²³ molecules/mole

Therefore, 67 g of sodium acetate is equal to a certain number of molecules, which you can find by following the steps above.

User Miralem Cebic
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