Question

Graph the equation after rewriting it on in slope intercept form. 2y-4=3x

Answer 1

We will solve as follows:

First, we rewrite it in slope-intercept form:

`2y-4=3x\Rightarrow2y=3x+4`
`\Rightarrow y=(3)/(2)x+2`

Second, to graph it we find two points using the equation and then plot the line using them. I will find the points for which x = 0 & y = 0, but any point in the line will work. That is:

*For x = 0:

`y=(3)/(2)(0)+2\Rightarrow y=2`

So, we have the point:

`A(0,2)`

*For y = 0:

`2(0)-4=3x\Rightarrow3x=-4`
`\Rightarrow x=-(4)/(3)`

So, we have the point:

`B(-(4)/(3),0)`

Now, we plot the line using those points: