Question

Label the states of each compound in the reaction: CuSO4( ) + 2KOH( ) --> Cu(OH)2( ) + K2SO4( ).

Answer 1

The states of the compounds in the reaction are: CuSO4(aq), KOH(aq), Cu(OH)2(s), K2SO4(aq).

Step-by-step explanation:

The states of each compound in the reaction CuSO4(aq) + 2KOH(aq) → Cu(OH)2(s) + K2SO4(aq) are as follows:

1. CuSO4(aq) - aquous solution
2. KOH(aq) - aquous solution
3. Cu(OH)2(s) - solid
4. K2SO4(aq) - aquous solution

So, copper (II) sulfate and potassium hydroxide react to form copper (II) hydroxide, which is a solid precipitate, and potassium sulfate, which remains in aqueous solution.