171k views
2 votes
If g is a constant function, f(x) = 2x + 7, and f(g(f(2))) = 15, then what is the value of g(f(g(2)))? (it must be 4 but how)

Options:
A) g(f(g(2)) = 4
B) g(f(g(2)) = 2
C) g(f(g(2)) = 7
D) g(f(g(2)) = 15

User Meva
by
8.2k points

1 Answer

2 votes

Final answer:

To find g(f(g(2))), understand that g is a constant function. Since f(g(f(2))) = 15 and f(x) = 2x + 7, g(f(g(2))) equals the constant value of g, which is 4.

Step-by-step explanation:

The question asks to find the value of g(f(g(2))) given that g is a constant function, f(x) is defined as f(x) = 2x + 7, and that f(g(f(2))) = 15. To approach this, we first need to work out f(2), which gives us f(2) = 2(2) + 7 = 11. Since g is a constant function, it means g(anything) will always yield the same value, hence g(11) and g(2) are equal. To find this constant value, we use the provided equation f(g(f(2))) = 15. Substituting the known value of f(2), we have f(g(11)) = 15, and from the definition of f(x), we get 2g(11) + 7 = 15, leading to g(11) = 4 after solving. This implies that g(x) at any x equals 4. Thus, g(f(g(2))) is just g(something), which we've established is 4, leading to the correct answer being g(f(g(2))) = 4.

User Webthusiast
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories