Question

Find the separate equation of the straight line represented by the following single equation: 2x^2 + 3xy + y^2 + 5x + 2y - 3 = 0.

(a) 2x + y - 1 = 0
(b) x + y + 3 = 0
(c) 3x + 2y + 5 = 0
(d) 5x + 3y - 2 = 0

Answer 1

The equation of the straight line is 2x + y + 5 = 0.

Step-by-step explanation:

To find the separate equation of the straight line represented by the given equation, you need to rewrite the equation in the form y = mx + c, where m is the slope of the line and c is the y-intercept.

By rearranging the equation 2x^2 + 3xy + y^2 + 5x + 2y - 3 = 0, we can rewrite it as y = -2x -5.

Thus, the separate equation of the straight line is 2x + y + 5 = 0.