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A gas occupies 12.3 liters at a pressure of 0.0526 atm. What is the volume when the pressure is increased to 0.0790 atm?

User Balanivash
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Final answer:

To solve this problem, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to its pressure when temperature and amount of gas are held constant.

Step-by-step explanation:

To solve this problem, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to its pressure when temperature and amount of gas are held constant. Boyle's Law can be represented by the equation P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

In this case, the initial volume V1 is given as 12.3 liters at a pressure of 0.0526 atm. The final pressure P2 is given as 0.0790 atm. We can plug these values into the equation and solve for V2:

P1V1 = P2V2

(0.0526 atm)(12.3 L) = (0.0790 atm)(V2)

Solving for V2:

V2 = (0.0526 atm)(12.3 L) / (0.0790 atm) = 8.18 L

Therefore, the volume when the pressure is increased to 0.0790 atm is 8.18 liters.

User Sepehr Behroozi
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