Question

Calculate the volume of an ideal gas with 5.3 moles at a pressure of 3.00 atm and a temperature of 308.15 K.

A) 5.84 L
B) 7.12 L
C) 9.67 L
D) 11.22 L

Answer 1

The volume of an ideal gas, use the Ideal Gas Law PV=nRT. Given 5.3 moles, 3.00 atm pressure, and 308.15 K temperature, the volume is calculated to be 44.952145 L, which does not match the provided options.

Step-by-step explanation:

To calculate the volume of an ideal gas using the Ideal Gas Law, we apply the formula PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Given:

• Number of moles (n) = 5.3
  
• Pressure (P) = 3.00 atm
  
• Temperature (T) = 308.15 K
  
• Ideal gas constant (R) = 0.08205 L·atm/mol·K

Plugging these values into the formula, we get:

V = nRT/P

V = (5.3 mol)(0.08205 L·atm/mol·K)(308.15 K)/(3.00 atm)

The atmospheres cancel out, as do the moles and Kelvin, leaving us with the volume in liters:

V = 44.952145 L

However, this answer is not an option, indicating a calculation error. Upon review, if the student computed correctly, the correct option should be in the provided choices.