Final answer:
To make a 1 M solution of NaCl in 2.2 L of water, you need to use 128.568 grams of NaCl. The calculation is based on the molar mass of NaCl which is 58.44 g/mol.
Step-by-step explanation:
To calculate the amount of NaCl needed to make a 1 M solution, we'll first need to be clear about what a 1 M solution means. A 1 M (molar) solution has 1 mole of solute per liter of solution. Given that the molar mass of NaCl is 58.44 g/mol, this means we would need 58.44 g of NaCl to make a 1 L solution. Since the student's question is about making this solution in 2.2 L of water, we need to multiply the amount of NaCl by 2.2.
Calculating the required NaCl:
1 mole of NaCl = 58.44 g
For a 1 M solution in 1 L of water, we need 58.44 g of NaCl.
To find out how much NaCl we need for 2.2 L, we'd perform the following calculation:
58.44 g/mole × 2.2 L = 128.568 g
Therefore, the answer to the student's question is that approximately 128.568 grams of NaCl (rounded to 129 g for simplification) are required, which means none of the provided options is correct.