Question

A soccer ball is kicked at 15 m/s at an angle of 10 degrees. What is the horizontal component of the velocity?

A. 2.60 m/s
B. 2.64 m/s
C. 14.1 m/s
D. 14.8 m/s

Answer 1

The horizontal component of the velocity of a soccer ball kicked at a speed of 15 m/s and an angle of 10 degrees is approximately 14.8 m/s.

Step-by-step explanation:

To find the horizontal component of the velocity, we can use the formula:

Horizontal component of velocity = initial velocity * cos(angle)

Given that the initial velocity is 15 m/s and the angle is 10 degrees, we can plug these values into the formula:

Horizontal component of velocity = 15 m/s * cos(10 degrees)

Using a scientific calculator, we find that the horizontal component of velocity is approximately 14.8 m/s.