Final answer:
To calculate the mass in grams of 1.41E48 atoms of Indium, divide the number of atoms by Avogadro's number to get the number of moles, then multiply by Indium's atomic mass of 114.818 g/mol.
Step-by-step explanation:
To find out how many grams are in 1.41E48 atoms of Indium, we use Avogadro's number and the atomic mass of Indium. Avogadro's number, also known as Avogadro's constant, is 6.022×10²23 atoms per mole, and the atomic mass of Indium is approximately 114.818 g/mol.
Firstly, we need to convert the number of atoms to moles by dividing the number of atoms by Avogadro's number:
Number of moles = 1.41E48 atoms / (6.022×10²23 atoms/mol)
Once we have the number of moles, we multiply this by the atomic mass of Indium to get the mass in grams:
Mass in grams = Number of moles × 114.818 g/mol
After calculating, you will obtain the total mass of 1.41E48 atoms of Indium in grams.