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O calculate the volume of gas at normal temperature and pressure (NTP), you can use the ideal gas law. The conditions for NTP are 0°C and 1 atm pressure. Given that the gas is at 27°C and 640 mm Hg (0.84 atm), you can use the ideal gas law:

V1 / (T1 * P1) = V2 / (T2 * P2)


V2 ≈ 324.55 ml

So, the volume of the gas at normal temperature and pressure is approximately 324.55 ml.

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Final answer:

Using the ideal gas law, the volume of a gas at STP can be calculated, and the combined gas law allows us to convert an initial gas volume to STP conditions.

Step-by-step explanation:

The ideal gas law can indeed be used to calculate the volume of a gas at standard temperature and pressure (STP), which is 0°C (273.15 K) and 1 atm (101.325 kPa). The law is expressed as PV = nRT, where P is pressure, V is volume, T is temperature in Kelvins, n is the amount of gas in moles, and R is the gas constant.

At STP, one mole of any gas occupies 22.4 L, known as the standard molar volume. To adjust gas volume to STP from another set of conditions (such as the given 27°C and 640 mm Hg), the combined gas law can be employed. For example, if a gas previously occupies a volume of 324.55 ml at 27°C and 0.84 atm, the volume at STP can be found by setting up the following equation: V1 / (T1 * P1) = V2 / (T2 * P2), solving for the new volume (V2).

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