Final answer:
The current going through a circuit with a 9-volt battery and 10 ohms of resistance is 0.9 amperes. The power dissipated in this circuit is 8.1 watts.
Step-by-step explanation:
To calculate the current going through a circuit with a 9-volt battery and 10 ohms of resistance, we use Ohm's law, which is I = V / R. Here, 'I' stands for current in amperes (A), 'V' is voltage in volts (V), and 'R' is resistance in ohms (Ω).
In this case, V = 9 volts and R = 10 ohms, so the current 'I' is 9 V / 10 Ω = 0.9 A. Thus, the current going through the circuit is 0.9 amperes.
The power dissipated in the circuit can also be calculated using the formula P = I2 * R, where 'P' represents power in watts. The power dissipated in this circuit is P = (0.9 A)2 * 10 Ω = 8.1 watts.