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A car is traveling at a constant velocity of 5 m/s for 10 seconds. It then áccelerates at a rate of 2 m/s^2 for an acdditional 10 seconds. At the end of 20 seconds, how far has the car gone?​

User Lomanf
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1 Answer

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Final answer:

The car travels a total distance of 150 meters at the end of 20 seconds.

Step-by-step explanation:

The car is traveling at a constant velocity of 5 m/s for 10 seconds, so we can calculate the distance using the formula:

Distance = velocity * time

Distance = 5 m/s * 10 s = 50 meters

After the 10 seconds, the car accelerates at a rate of 2 m/s^2 for an additional 10 seconds. To find the distance during this time, we can use the formula for uniformly accelerated motion:

Distance = initial velocity * time + 0.5 * acceleration * time^2

During this time, the initial velocity is 5 m/s, the time is 10 s, and the acceleration is 2 m/s^2:

Distance = 5 m/s * 10 s + 0.5 * 2 m/s^2 * (10 s)^2 = 100 meters

Therefore, the total distance traveled by the car at the end of 20 seconds is:

Total Distance = 50 meters + 100 meters = 150 meters

User Donnyton
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