Question

A force of 10 Newtons is applied for 5 seconds on an object with a mass of 2 kilograms. The object was initially at rest. What is the final velocity of the object? Select the formula that will give the correct answer.

1. V(final)=(10)(10)/2 +2
2. V(final)=(10/27/5 +2
3. V(final)=(10/10)/5 +2
4. V(final)=(10)(5)/2 + 0
5. V(final)=(5,5)/2 +0

Answer 1

The final velocity of an object with a mass of 2 kg after a force of 10 Newtons is applied for 5 seconds is 25 m/s. The correct formula is V(final) = (force × time) / mass + initial velocity, with the initial velocity being zero.

Step-by-step explanation:

Given that a force of 10 Newtons is applied to a 2 kg object initially at rest for 5 seconds, we need to determine the final velocity of the object. The correct formula to find the final velocity is based on Newton's second law of motion (F = ma) and the definition of acceleration (a = Δv/Δt).

Steps to Calculate Final Velocity

Calculate the acceleration using Newton's second law: a = F/m = 10 N / 2 kg = 5 m/s².

1. Determine the change in velocity (Δv) since the object starts from rest (Δv = a × t).
2. Now, Δv = 5 m/s² × 5 s = 25 m/s.
3. The final velocity (v_final) is the change in velocity since the initial velocity is 0 m/s. So, v_final = Δv = 25 m/s.

The correct formula and answer from the given options is:

4. V(final) = (10)(5)/2 + 0