64.3k views
4 votes
A = 13, d = 6, n=12
Evaluate this arithmetic series.

User Methyl
by
7.3k points

1 Answer

5 votes

Final answer:

The sum of the first 12 terms of the arithmetic series with a first term of 13 and a common difference of 6 is 552.

Step-by-step explanation:

To evaluate an arithmetic series, we use the formula Sn = n/2(2a + (n - 1)d), where Sn is the sum of the series, n is the number of terms, a is the first term, and d is the common difference between the terms.

Given a = 13, d = 6, and n = 12, we can substitute these values into the formula to find the sum of the first 12 terms.

S12 = 12/2(2(13) + (12 - 1)6) = 6(26 + 66) = 6(92) = 552.

Therefore, the sum of the first 12 terms of the arithmetic series is 552.

User Pavan Keerthi
by
8.0k points