Final answer:
To find Maggie's final velocity after accelerating for a distance of 15 meters, we use the equation v_f^2 = vi^2 + 2ad. With an initial velocity of 2 m/s and an acceleration of 4 m/s^2, her final velocity is approximately 11.49 m/s.
Step-by-step explanation:
The question involves finding Maggie's final velocity after she accelerates for a distance of 15 meters. To solve this, we need to use the kinematic equation that relates distance (d), initial velocity (vi), acceleration (a), and final velocity (vf).
Since we know the distance (d), initial velocity (vi), and acceleration (a), the kinematic equation we can use is:
vf2 = vi2 + 2ad
Plugging in the values: vi = 2 m/s, a = 4 m/s2, and d = 15 m, we get:
vf2 = (2 m/s)2 + 2 × (4 m/s2) × (15 m)
Solving for vf, we find that Maggie's final velocity is the square root of this expression. Remember, when taking the square root, consider only the positive value, as velocity is directional and we assume Maggie continues in the same direction as her initial movement.
Final velocity (vf) = √([22 + 2×4×15] m2/s2)
Final velocity (vf) = √(132 m2/s2)
Final velocity (vf) = 11.49 m/s (approximately)
Therefore, Maggie's final velocity after accelerating over the distance of 15 meters is approximately 11.49 m/s.