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If 0.32 moles of water vapor are produced in the reaction, how many moles of oxygen gas were used in the reaction?

User Evhz
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Final answer:

To find the number of moles of oxygen gas used in the reaction, we need to look at the balanced chemical equation and use the mole ratio between water and oxygen. In this case, 0.16 moles of oxygen gas were used.

Step-by-step explanation:

The question asks how many moles of oxygen gas were used in a reaction that produced 0.32 moles of water vapor. To find the answer, we need to look at the balanced chemical equation for the reaction. If we know the mole ratio between water and oxygen, we can determine the number of moles of oxygen gas used. Let's assume the reaction is:

2H2(g) + O2(g) -> 2H2O(g)

From the equation, we can see that 2 moles of water are produced for every 1 mole of oxygen gas used. Therefore, if 0.32 moles of water vapor are produced, we can calculate the moles of oxygen gas as follows:

(0.32 moles of water) x (1 mole of O2 / 2 moles of H2O) = 0.16 moles of O2

So, 0.16 moles of oxygen gas were used in the reaction.

User Panidarapu
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