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Given the points (3,1) and (5,9), write the equation of a line in point/slope form.

User Llamarama
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1 Answer

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Final answer:

The equation of the line in point/slope form is y = 4x - 11.

Step-by-step explanation:

The equation of a line in point/slope form is given by y = mx + b, where m is the slope and b is the y-intercept.

Using the given points (3,1) and (5,9), we can calculate the slope using the formula m = (y2-y1)/(x2-x1). Substituting the values, we get m = (9-1)/(5-3) = 8/2 = 4.

Now, we can substitute the slope and one of the points into the equation to find the y-intercept. Using the point (3,1), we get 1 = 4(3) + b. Solving for b, we find b = -11.

Therefore, the equation of the line in point/slope form is y = 4x - 11.

User Xangr
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