Final answer:
The value of the sine of ∠D in ΔCDE to the nearest hundredth is 0.32.
Step-by-step explanation:
The student has asked: What is the value of the sine of ∠D in ΔCDE to the nearest hundredth, if ∠E = 90°, DC = 37, ED = 35, and CE = 12?
In a right triangle, the sine of an angle is equal to the length of the side opposite the angle divided by the length of the hypotenuse. Since ∠E is 90°, ΔCDE is a right triangle with DC as the hypotenuse.
The sine of ∠D is the length of the opposite side, which is CE, divided by the hypotenuse, which is DC. So, sin(∠D) = CE / DC = 12 / 37. Calculating this gives us 0.3243, which, when rounded to the nearest hundredth, is 0.32.