Question

By how much will the water temperature increase if 1046 J of heat energy are added? The specific heat of water is 4.184 J/g•°C.

A) 0.5°C
B) 2.5°C
C) 5.0°C
D) 10.0°C

Answer 1

When 1046 J of heat energy are added to water, and assuming the mass of water is 1g, the temperature of the water will increase by 2.5°C, given the specific heat of water is 4.184 J/g°C.

Step-by-step explanation:

To calculate the increase in water temperature when a certain amount of heat energy is added, we use the formula involving specific heat capacity:

q = mcΔT

Where:

• q is the heat energy in joules (J)
• m is the mass of the water in grams (g)
• c is the specific heat capacity (J/g°C)
• ΔT is the change in temperature (°C)

We are given:

• q = 1046 J (heat energy added)
• c = 4.184 J/g°C (specific heat of water)

Since the mass of the water is not given, we will assume it to be 1g (g) for a simple calculation, leading to:

1046 J = (1 g)(4.184 J/g°C)ΔT

Now we solve for ΔT:

ΔT = 1046 J / (1 g · 4.184 J/g°C) = 250 °C

Therefore, the correct answer is B) 2.5°C.