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If QT = 3x – 4 and Q'T = 6x – 16, then what is the length of QQ'?

A) 2x – 12
B) 3x + 12
C) 3x – 12
D) 6x – 20

User Feifei
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1 Answer

3 votes

Final answer:

The length of QQ' is found by subtracting QT from Q'T, resulting in QQ' = Q'T - QT = (6x - 16) - (3x - 4) which simplifies to 3x - 12. Hence, the correct answer is option C, 3x - 12.

Step-by-step explanation:

To find the length of QQ', we can evaluate the expressions given for QT and Q'T. Assuming that these line segments are on the same line and that Q' lies between Q and T, the length of QQ' can be found by subtracting the length of QT from Q'T.

We have QT = 3x – 4 and Q'T = 6x – 16. So, QQ' = Q'T – QT, which simplifies to:

(6x – 16) – (3x – 4)

After subtracting, we combine like terms:

(6x – 3x) + (–16 + 4)

This results in 3x – 12.

Therefore, the length of QQ' is 3x – 12, which corresponds to option C.

User Yman
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