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What is the Gravitational Potential Energy at the top of the MegaRamp for the 70 kg skateboarder? (g = 10 N/kg)

A) 13,300 J
B) 14,700 J
C) 18,900 J
D) 19,600 J

User Danijela
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1 Answer

2 votes

Final answer:

To determine the skateboarder's Gravitational Potential Energy at the top of the MegaRamp, we would use the formula GPE = mgh, with a mass of 70 kg and gravitational acceleration of 10 N/kg. The corresponding height details are not provided in the question but using the given formula, we match the calculated GPE to one of the provided multiple-choice answers.

Step-by-step explanation:

To calculate the Gravitational Potential Energy (GPE) at the top of the MegaRamp for the skateboarder, we can use the formula GPE = mgh, where:

  • m is the mass of the skateboarder (70 kg),
  • g is the acceleration due to gravity (10 N/kg as given in the question), and
  • h is the height of the MegaRamp.

The height of the MegaRamp is not provided, but as we are given multiple-choice answers, we can conclude that the necessary height must have been provided in an earlier part of the question or accompanying materials. Assuming the correct height has been factored into the provided choices, we calculate GPE using an unknown height h that corresponds to one of the answer choices provided.

To find the correct answer, we would calculate GPE using the provided mass and gravitational acceleration, and compare it to the choices given: A) 13,300 J, B) 14,700 J, C) 18,900 J, and D) 19,600 J. The correct answer must be among these and corresponds to the correct value of h in meters that would result in the GPE matched by one of the answer options.

User Splintor
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