Question

A land rover drops, from rest, a vertical distance of 1,000 meters to the surface of a planet in 15 seconds. What is the magnitude of the acceleration due to gravity on the planet?

a. 6.67 m/s²
b. 22.22 m/s²
c. 44.44 m/s²
d. 66.67 m/s²

Answer 1

The magnitude of the acceleration due to gravity on the planet is 22.22 m/s².

Step-by-step explanation:

To find the magnitude of the acceleration due to gravity on the planet, we can use the equation of motion for an object in free fall:

Distance fallen (d) = Initial velocity (v0) * Time taken (t) + 0.5 * Acceleration (a) * Time taken (t)2

Since the land rover started from rest, the initial velocity (v0) is 0. We can rearrange the equation to solve for acceleration:

a = (2 * d) / t2

Substituting the values of distance fallen (d = 1000 m) and time taken (t = 15 s) into the equation:

a = (2 * 1000) / (152) = 22.22 m/s²

Therefore, the magnitude of the acceleration due to gravity on the planet is 22.22 m/s².