Final answer:
The polynomial that models the height of the ball is -161t^2 + 20t + 4.
Step-by-step explanation:
The polynomial that models the height of the ball is option B) -161t^2 + 20t + 4.
To solve this problem, we can use the formula for projectile motion. In this case, the ball is thrown vertically with an initial velocity of 20 feet per second and a starting height of 4 feet. The formula for the height of an object in projectile motion is given by:
h(t) = h0 + v0t + (1/2)at^2
Where h(t) is the height of the object at time t, h0 is the initial height, v0 is the initial velocity, a is the acceleration (which is equal to -32 feet per second squared for objects in free fall), and t is time.
Plugging in the given values, the polynomial that models the height of the ball is -161t^2 + 20t + 4.