Question

"A man with type AB blood marries a woman with type B blood. Her mother has type O blood. List the expected phenotype and genotype frequencies of their children."

Answer 1

A man with an AB blood type and a woman with a BO genotype could have children with phenotypes of AB, A, or B. The genotype frequencies are 25% AB, 25% AO, and 50% BB or BO. There is no chance of blood type O since the man doesn't have an O allele.

Step-by-step explanation:

Expected Phenotype and Genotype Frequencies of Children

The blood type inheritance question involves a man with an AB blood type and a woman with a B blood type who has an O-type mother. This indicates that the woman must have one B allele (from her father) and one O allele (since O is recessive, and her mother has OO genotype). Therefore, the woman's genotype is BO.

The man with AB blood type has both A and B alleles (genotype AB). The possible gametes for the man are A and B, and the possible gametes for the woman are B and O. When these gametes combine during fertilization, they can produce offspring with the following genotypes and resultant phenotypes: AB (blood type AB), AO (blood type A), BB (blood type B), and BO (blood type B).

As a result, the children could have phenotypes of either AB, A, or B. There will be a 25% chance for blood type AB, a 25% chance for blood type A, and a 50% chance for blood type B. There will be no possibility of blood type O since the man does not carry the O allele.