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Ricky Bobby is racing around the track with a velocity of 60 m/s. He slams on his brakes and comes to a complete stop. If his car and he have a combined mass of 2700 kg, how much work did his brakes do? Formula.

User Afonseca
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The brakes did 4,860,000 joules of work to stop Ricky Bobby's racing car with a mass of 2700 kg and an initial velocity of 60 m/s.

The question is asking us to calculate the work done by the brakes to bring Ricky Bobby's racing car to a halt. According to the work-energy principle, the work done by the brakes is equal to the change in kinetic energy of the car. Since work is the force exerted over a distance and kinetic energy is ½ mass times velocity squared, we can express the work done by the brakes (W) as:

W = ½ mv²

This formula assumes that Ricky Bobby's car is coming to a stop without any external work other than the brakes being applied. Given that the car's mass (m) is 2700 kg and its initial velocity (v) is 60 m/s, we can use the formula to calculate the work:

W = ½ x 2700 kg x (60 m/s)²

W = ½ x 2700 kg x 3600 (m²/s²)

W = 0.5 x 2700 kg x 3600 m²/s²

W = 4,860,000 J (joules)

Therefore, the brakes did 4,860,000 joules of work to stop Ricky Bobby's racing car.

User Averias
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