Question

Richard and Teo have a combined age of 33. Richard is 6 years older than twice Teo's age. How old are Richard and Teo?

a) Richard is 20, Teo is 13
b) Richard is 27, Teo is 6
c) Richard is 14, Teo is 19
d) Richard is 33, Teo is 0"

Answer 1

Using algebra, we assign variables to Teo and Richard's ages and create equations based on the given information. We find that Teo is 9 years old and Richard is 24 years old, which is not listed in the provided options.

Step-by-step explanation:

To solve the problem, let's define some variables. Let Teo's age be T and Richard's age be R. The problem gives us two equations:

• R + T = 33 (the combined age of Richard and Teo)
• R = 2T + 6 (Richard is 6 years older than twice Teo's age)

Substituting the second equation into the first, we get:

• (2T + 6) + T = 33
• 3T + 6 = 33
• 3T = 27
• T = 9

Now that we know Teo's age, we can find Richard's age:

• R = 2(9) + 6
• R = 18 + 6
• R = 24

Therefore, Richard is 24 years old, and Teo is 9 years old. So the correct answer is not listed in the options provided by the student.