Final answer:
The new volume of the balloon when the pressure drops to 75 kPa is approximately 16.29 L, calculated using Boyle's Law.
Step-by-step explanation:
The student's question involves calculating the change in volume of a balloon when the pressure changes, keeping the temperature and the number of moles of gas constant. This situation is described by Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature and the amount of gas remain constant (P1V1 = P2V2). To find the new volume (V2) when the pressure drops to 75 kPa, we use the initial conditions of the balloon (12.2 L at 110 kPa) and solve for V2:
V2 = (P1 x V1) / P2
Substitute the known values: V2 = (110 kPa x 12.2 L) / 75 kPa = 16.2933 L (rounded to 16.29 L)
Therefore, the new volume of the balloon will be approximately 16.29 L when the pressure drops to 75 kPa.