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H(n)=63⋅(−1/3)^n. Complete the recursive formula of h(n).
h(1) = ?
h(n) = h(n-1) * ?

User KayakDave
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Final answer:

The recursive formula for the given function h(n) = 63 * (-1/3)^n is h(n) = h(n-1) * (-1/3), with h(1) = 63.

Step-by-step explanation:

The given function is represented by the formula h(n) = 63 * (-1/3)^n. To find the recursive formula, we need to express h(n) in terms of h(n-1). To do this, we substitute n-1 for n in the given function: h(n-1) = 63 * (-1/3)^(n-1). Now we can complete the recursive formula:

  1. Initial condition: h(1) = 63 * (-1/3)^(1-1) = 63 * (-1/3)^0 = 63 * 1 = 63
  2. Recursive relation: h(n) = h(n-1) * (-1/3) for n > 1

User Covi
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