Final answer:
The molarity of the NaOH solution, when 23.5g of NaOH is dissolved in 0.683 L of water, is approximately 0.860 M.
Step-by-step explanation:
To calculate the molarity of the NaOH solution, we first need to determine the number of moles of NaOH. The molar mass of NaOH is approximately 40 g/mol. Therefore, 23.5 g of NaOH is equivalent to 23.5 g ÷ 40 g/mol = 0.5875 mol of NaOH.
Since molarity is defined as the number of moles of solute per liter of solution, we can calculate the molarity of the NaOH solution using the formula:
Molarity = moles of solute ÷ liters of solution
Substituting the values we have:
Molarity = 0.5875 mol ÷ 0.683 L = ≈0.860 M
Therefore, the molarity of the NaOH solution is approximately 0.860 M, rounded to three significant figures.