Question

Which equation represents a line that is perpendicular to y = 5x + 2 and goes throughthe point (-10, 3)?

Answer 1

The slope of the given line is 5 because that's the coefficient of x.

Then, we use the following formula to find the perpendicular slope.

`\begin{gathered} m=-(1)/(m_1) \\ m=-(1)/(5) \end{gathered}`

Then, we use the point-slope formula.

`\begin{gathered} y-y_1=m(x-x_1)_{} \\ y-3=-(1)/(5)(x-(-10))_{} \\ y-3=-(1)/(5)(x+10) \\ y=-(1)/(5)x-2+3 \\ y=-(1)/(5)x+1 \end{gathered}`

Therefore, the equation is y = -1/5x + 1.