Question

Drag the tiles to the correct boxes to complete the pails.Watch each quadratic equation with its solution set.232_91-1=02:2_85-3=02-2-83+5= 0232-105-3=02-2-93+5=043

Answer 1

The general equation of a quadratic equation is given by

`y=ax^2+bx+c`

The solution to the equation, using the formula method is given by

`\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

To solve the question, we will apply the formula above to match the options provided

Step1: Match

`2x^2-8x+5=0`

In this case, a=2, b=-8, c=5

substituting into the formula

we will obtain

`\frac{8\pm\sqrt[]{24}}{4}`

simplifying further

Upon factoring out 2

We will obtain:

`\frac{4\pm\sqrt[]{6}}{2}`

Step2: Match

`2x^2-10x-3=0`

In this case,

a=2, b=-10 and c =-3

substituting into the quadratic formula

we will obtain

`\frac{10\pm2\sqrt[]{19}}{4}`

simplifying further

we will obtain

`\frac{5\pm\sqrt[]{19}}{2}`

Step 3: Match

`2x^2-8x-3=0`

In this case: a=2, b=-8 and c=-3

substituting into the quadratic formula

we will obtain

`\frac{8\pm2\sqrt[]{22}}{4}`

Simplifying further

we will obtain

`\frac{4+\sqrt[]{22}}{2}`

Step 4: Match

`2x^2-9x-1=0`

In this case: a=2, b=-9 and c =-1

substituting into the quadratic formula

we will obtain

`\frac{9+\sqrt[]{89}}{4}`

Step 5: Match

`2x^2-9x+6=0`