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The members of the boosters organization at your high school bought new balls for the school. They spent $14.00 per basketball and $21.00 per football, spending a total of $504.00. They bought 4 more footballs than basketballs. How many of each type of ball did they buy?

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Final answer:

The boosters organization bought 12 basketballs and 16 footballs.

Step-by-step explanation:

Let's assume that the number of basketballs bought is x. Since they bought 4 more footballs than basketballs, the number of footballs bought is x+4. The cost of each basketball is $14.00 and the cost of each football is $21.00. We can set up the following equation to represent the total cost of the balls:

14x + 21(x+4) = 504

Simplifying the equation:

14x + 21x + 84 = 504

Combining like terms:

35x + 84 = 504

Subtracting 84 from both sides:

35x = 420

Dividing both sides by 35:

x = 12

Therefore, they bought 12 basketballs and 16 footballs.

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